For a normal distribution given a standard deviation of 3.8 in a mean of 54 what percent lies above 48
A 0.1690
B 0.0571
C 0.7660
D 0.9429

choice D.) 0.9429

Step-by-step explanation:

Given a Normal data set

mean u = 54

standard deviation s = 3.8

we want P( X > 48)

Standardize this probability so we can use Z-scores.

P( X > 48) = P( (X - u)/s > (48 - 54)/3.8 ) = P(Z >  -1.5789)

so  I look for P ( Z > 1.5789) = 0.0571

so  P(Z > -1.5789) = 1 - P(Z > 1.5789) = 1 - 0.0571 = 0.9429

K(x) = (1/4)^x

(1,4) when x = 1, k(1) = (1/4)^1 = 1/4FALSE
(3, 1/64) when x = 3, k(3) = (1/4)^3 = 1/64TRUE
(-1,4) when x = -1, k(-1) = (1/4)^-1 = 4TRUE
(0, 1/4) when x = 0, k(0) = (1/4)^0 = 1FALSE

answer
(3, 1/64)
(-1,4)