For all real numbers x ⊕ y = x + 3 y What is 4 ⊕ 3?

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13

7

12

15

36

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Ответ:

thesusan7494

31.03.2021

Mathematics

Hello,

4. you have sequences defined by the first term and a recursive relation.

$a_1=3\\\\a_n=2a_{n-1} \ \ \text{ for n} 1$

Take n = 2, it gives

a_2=2a_1 , right?

But you know a_1=3

so a_2=2a_1=2*3=6

This is the second term. You are asked to find the first three terms.

Now, let's take n = 3

a_3=2a_2=2*6=12

So the first three terms are 3, 6, 12.

$a_1=12\\\\a_2=\dfrac{1}{2}a_1+1=\dfrac{12}{2}+1=6+1=7 \\ \\a_3=\dfrac{1}{2}a_2+1=\dfrac{7}{2}+1=\dfrac{9}{2}$

$a_1=10\\ \\a_2=-3a_1=-3*10=-30\\\\a_3=-3a_2=-3*(-30)=90$

10.

$a_1=2\\\\a_2=-1\\\\a_3=a_2+a_1=-1+2=1\\\\a_4=a_3+a_2=1-1=0$

Do not hesitate if you have any question.

Thank you

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For all real numbers x ⊕ y = x + 3 y What is 4 ⊕ 3? Group of answer choices 13 7 12 15 36