For any integer x, x squared -x will always produce

Ответ:

estherboocx

11.03.2022

(x^2 - x) will always have an even value.

Step-by-step explanation:

We are given an integer x.

Let x be even, then it can be written in the form x = 2n, where n is an integer.

If we evaluate,

(x^2 - x) = (2n)^2 - 2n = 4n^2 - 2n = 2(2n^2 - n)

Thus, it have an even value.

If we take x to be an odd integer, then,it can be written in the form x = 2n+1, where n is an integer.

(x^2 - x) = (2n+1)^2 - 2n = 4n^2 + 2n = 2(2n^2 + n)

Thus, it have an even value.

Thus,

(x^2 - x) will always have an even value.

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