FOR EASY BRAINLIEST ANSWER THIS WITH EXPLANATION!ASAP Question: A cashier has 20 bills, all of which arc ten-dollar or twenty-dollar bills. The value of the money is $250. How many of cach type docs he have?

a cashier has 20 bills, all of which are $10 or $20 bills. The total value of the money is $330. How many of each type does the cashier have?

Found 2 solutions by richard1234, mananth:Let a,b be the number of $10 and $20 bills, respectively. We have the system of equations

10a + 20b = 330

a + b = 20 (since there are 20 bills)

We can multiply the second equation by 10 to obtain 10a + 10b = 200. Substituting into the first equation we have

(10a + 10b) + 10b = 330

200 + 10b = 330

b = 13, a = 7

So the cashier has seven $10 bills, 13 $20 bills.

Answer by mananth(16056) (Show Source): You can put this solution on YOUR website!

$10 bill x

$20 bill y

...

x+y=201

...

10+20y=330

/10

x+2y=332

multiply equation 1 by -1

-x-y-20

add this to (2)

-x+x-y+2y=-20+33

y = 13 $ 20 bills

x= 7 $10 bills

...

5 $20 bills

15 $10 bills

Step-by-step explanation:

x+y=20

10x+20y=250

thats all I remember about substitution/elimination lol