For how many different values of θ between 0 and 2π radians is sec x = csc x ?

Okay,let's simplify that.if secx=cscx,it will be also true that cosx=sinx.

in first quadrant,/4 could be an answer
in second quadrant,sin is positive but cos is negative.so,there is NO such angle
in third quadrant,(+/4) is a answer(where both of them are negative)
in fourth quadrant,cos is positive but sin negative...so there isnt any angle.
are the answers

The answer is D. 

X/-5 = 2
x =2 * -5
Therefore, x is less than -10