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Asantetaedog8934
15.11.2019 •
Mathematics
For the following relation on the set {x: x∈ζ and 1 ≤ x ≤ 12}.
list:
(a) the ordered pairs belonging to the relation:
(b) the transitive closure
s = {(x, y): 2x = 3y}
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Ответ:
We know that x can be any number from 1 to 12. If 2x must be equal to 3y, then 2x must be a multiple of 3. Here's the list of all possible values:
So, the only values for x when 2x is a multiple of 3 are
So, the ordered pairs are
For the transitive closure, you have to look for pairs like (a,b), (b,c), and add the pair (a,c), so that the relation becomes transitive. In our example, we only have the pairs (9,6) and (6,4), so we must add the pair (9,4) in order to make the relation transitive. The transitive closure is thus
Ответ:
5 plus 5 equals 10 and 8 plus -8 equals 0 negative 4 plus minues negative 4 is -8 so 2 and with 3 plus 5 equals 10 answer= 8 + (-8)
Step-by-step explanation: the answer is 8 plus -8 because all the others are -8 10 and 8