For the following three vectors, what is 3c·(2a x b )?
a. 2.00 + 3.00 - 7.00
b. -3.00 + 3.00 + 2.00
c. 6.00 - 8.00

2 A x B = ( 2*(2 i + 3 j - 7 k ) x ( - 3 i + 3 j + 2 k )  ) =
= ( 4 i + 6 j - 14 k ) x ( - 3 i + 3 j + 2 k ) =
      i      j       k      i    j
= | 4     6    -14 |  4   6
    -3     3       2   -3   3
= 12 i + 42 j + 12 k - 8 j + 42 i + 18 k = 54 i + 34 j + 30 k
3 C * ( 2 A x B ) = 3 ( 6 i - 8 j + 0 k ) * ( 54 i + 34 j + 30 k ) =
= ( 18 i - 24 j + 0 k ) * ( 54 i + 34 j + 30 k ) =
= ( 18 * 54 ) j  - ( 24 * 34 k ) + ( 0 * 30 ) k = 972 i - 816 j

216

Step-by-step explanation:

I'm not really sure but that's what I got