For the function f(x)=\frac{\sqrt{x-2}}{8}f(x)= 8 x−2 , find f^{-1}(x)f −1 (x). f^{-1}(x)=\left(8\left(x+2\right)\right)^{2}f −1 (x)=(8(x+2)) 2 f^{-1}(x)=\left(8x\right)^{2}+2f −1 (x)=(8x) 2 +2 f^{-1}(x)=\left(8x+2\right)^{2}f −1 (x)=(8x+2) 2 f^{-1}(x)=8\left(x+2\right)^{2}f −1 (x)=8(x+2) 2

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