For the function u(t) = 3t+8 and s(t) = t^2, what is s(u(1))?

Please, see the attached file.

Thanks.

Solution:

We can graph using the intercepts:

(1) y-intercept, when x=0

y=4x-3→y=4(0)-3→y=0-3→y=-3

Point=(x,y)=(0,-3)

(2) x-intercept, when y=0

y=4x-3→0=4x-3

Solving for x: Adding 3 both sides of the equation:

0+3=4x-3+3

3=4x

Dividing both sides of the equation by 4:

3/4=4x/4

3/4=x

x=3/4=0.75

Point=(x,y)=(3/4,0)=(0.75,0)

With these pair of points (0, -3) and (0.75,0) we can draw the right line