Mathematics: . For vectors B⃗ =−iˆ−4jˆB→=−i^−4j^ and A⃗ =−3iˆ−2jˆA→=−3i^−2j^ , calculate (a) A⃗ +B⃗ A→+B→ and its magnitude and direction angle, and (b) A⃗ −B⃗ A→−B→ and its magnitude and direction angle.

. For vectors B⃗ =−iˆ−4jˆB→=−i^−4j^ and A⃗ =−3iˆ−2jˆA→=−3i^−2j^

Ответ:

cillalynn24

19.01.2022

Mathematics

Step-by-step explanation:

given are two vectors

$B=-i-4j\\A = 3i-2j$

a) A+B = sum of twovectors = simply adding corrsponding compnents

= 2i-6j

Magnitude of the above vector = $\sqrt{2^2+6^2} \\=2\sqrt{10}$

Direction is making an angle of arc tan (-3) with x axis

b) A-B = Difference

= 4i+2j

Magnitude of difference vector = $\sqrt{4^2+2^2} \\=2\sqrt{5}$

Direction is making an angle of arctan (1/2) with positive x axis.

(angle = arctan (jcomponent/icomponent)

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Ответ:

xelynncaldera

13.09.2022

Mathematics

X - y = 7...x = y + 7
3x - 2y = 8

3(y + 7) - 2y = 8 ...correct
3y + 21 - 2y = 8 <== here is the error...did not distribute correctly

answer is : step 3

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. For vectors B⃗ =−iˆ−4jˆB→=−i^−4j^ and A⃗ =−3iˆ−2jˆA→=−3i^−2j^ , calculate (a) A⃗ +B⃗ A→+B→ and its magnitude and direction angle, and (b) A⃗ −B⃗ A→−B→ and its magnitude and direction angle.

Ответ:

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