Mathematics: For which value of x is inequality 3(1+x) +6true?

For which value of x is inequality 3(1+x) +6true?

minileiva211

20.12.2021

For in the inequality to be true, X must be less than or equal to 1. That represented as an in equality is X < 1.

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ciarrap552

20.12.2021

x<1 true

Step-by-step explanation:

3(1+x)<+6= 3×1+3×X<+6=3+3x<6 then3x=6-3 solution 3x=3 devide by 3 both sides the answer is x=1 hence x<1 verified

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SakChan8367

04.06.2020

P(A and B) = P(AnB)

Step-by-step explanation:

$P( \frac{A}{B} ) = \frac{P(AnB)}{P(B)} \\from \: bayes \: theorem \\ P(AnB) = P(B) \times P( \frac{A}{B}) \\ = 0.45 \times 0.7 \\ = 0.315$

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