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jholland18
10.02.2021 •
Mathematics
Four biased coins, A, B, C and D are thrown.
The probability that each coin will land on Heads is shown in the table.
Coin Probability a) (i) Which coin is least likely to land on Heads?
А
0.66
(1)
0.066
(ii) Which coin is most likely to land on Heads?
С
(1)
60%
b) What is the probability that D will land on Tails?
(1)
B
D
Coin B is going to be thrown 4000 times.
c) Work out an estimate for the number of times
coin B will land on Heads.
(2)
Total marks: 5
Solved
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Ответ:
Please check explanations for answer
Step-by-step explanation:
Firstly, we need all the probability in the same decimal form
P(A) = 0.66
P(B) = 0.067
P(C) = 2/3 = 0.67
P(D) = 60/100 = 0.6
a) The least likely is the smallest value of decimal
This is 0.067 which is for coin B
most likely is the highest probability; this is C which is 2/3
b. Probability that D will land on tail is 1 - probability that it lands on head
= 1 - 0.6 = 0.4
c. Mathematically that is the product of the probability and the number of times it was thrown
That will be;
0.066 * 4000
= 264 times
Ответ:
100 / 10 = 10
10 / 10 = 1
so 1000 = 10^3