Mathematics: Four members from a 45-person committee are to be selected randomly to serve as chairperson, vice-chairperson, secretary, and treasurer. the first person selected is the chairperson; the second, the vice-chairperson; the third, the secretary; and the fourth, the treasurer. how many different leadership structures are possible?

Four members from a 45-person committee are to be

dessy6546

08.01.2022

3575880

Step-by-step explanation:

We need to use Permutation method,

$nPr= \frac{n!}{(n-r)!}$

Where n is the sample of size and r the combination considered, so

$n=45\\r=4\\45P4= \frac{45!}{(45-4)!}\\45P4 = 3575880$

There is 3575880 possibilities to make leadership structures in that committee

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marquetter7689

07.03.2020

Only x=-2 is an extraneous solution is the answer

Step-by-step explanation:

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