Mathematics: Four resistors are connected in series such that their total resistance is 50ohm . if the resistance of resistors is 5 ohm , 10ohm and 15 ohm respectively .find tue resistance of the fourth resistor

3/4 because if you multiply to get the LCM (16) it becomes 12/16 which is greater than 11/16...

Four resistors are connected in series such that

Ответ:

bommers144

07.01.2022

Mathematics

$\boxed{R_{4}=20\Omega}$

Step-by-step explanation:

If resistors are in series, so the current is the same in all of them. In this problem we have four resistors. So, we can get a relationship between the Equivalent resistance of series combination and the four resistors as follows:

$R_{eq}=R_{1}+R_{2}+R_{3}+R_{4}$

$R_{eq}$ is the total resistance $50\Omega$ . Moreover:

$R_{1}=5\Omega \\ R_{2}=10\Omega \\ R_{3}=15\Omega$

Therefore:

$50=5+10+15+R_{4} \\ \\ R_{4}=50-(5+10+15) \\ \\ R_{4}=50-30 \\ \\ \boxed{R_{4}=20\Omega}$

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Four resistors are connected in series such that their total resistance is 50ohm . if the resistance of resistors is 5 ohm , 10ohm and 15 ohm respectively .find tue resistance of the fourth resistor

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