Four times one number minus three times another number is 12. two times the first number added to three times to the second number is 6. find the numbers. write equations and solve the system using elimination

By using the elimination method, the first number is 3 and the second number is 0.

Translating the word problem into an algebraic expression, we have;

Four times one number minus three times another number is 12:

 ...equation 1.

Two times the first number added to three times to the second number is 6:

  ...equation 2.

Applying the elimination method, we have:

a = 3

For the value of the second number:

Read more on elimination method here: link

Step-by-step explanation:

x = first number, y = second number

4x - 3y = 12

2x + 3y = 6

add

6x = 18

x = 18/6

x = 3

4x - 3y = 12

4(3) - 3y = 12

12 - 3y = 12

-3y = 12 - 12

-3y = 0

y = 0

solution : (3,0)

Lol thanks for the points! :)

Step-by-step explanation: