G(n)=25−49(n−1) complete the recursive formula? my g(1)=25g(n)=g(n-1)+? what is ?

• g(1) = 25

• g(n) = g(n-1) -49

Step-by-step explanation:

You can get a clue by filling in n=2 in the explicit formula:

g(2) = 25 -49(2-1) = 25 -49 = g(1) -49

The explicit formula is of the form for an arithmetic sequence:

g(n) = g(1) +d(n-1) . . . . where g(1) is the first term and d is the common difference

Of course, this translates to the recursive formula ...

• g(1) = g(1)

• g(n) = g(n-1) +d

Here you have g(1) = 25, and d = -49. Filling these into the recursive form, you get ...

• g(1) = 25

• g(n) = g(n-1) -49

y-1/3x=17/3

Step-by-step explanation:

ax+by=c is standard form

first I'll start with slope interecept form and then we can change it to standard

y=mx+b

y=1/3x+b

4=1/3(-5)+b

4=-5/3+b

12/3+5/3=b

17/3=b

y=1/3x+17/3

to change to standard

y-1/3x=17/3