-Geometry 1 FIND THE QUADRANTS OF POINT P of triangle PST, a 45°-45°-90° triangle with vertices S(3, −5) and T(−4, 2) and mangleS = 90°. P is in Quadrant I.

Answer in simplest radical form.

Please help it would be very much appreciated (:

Coordinates of P:  (10,2)

Step-by-step explanation:

Slope of ST = (2-(-5))/(-4-3) = -1

angle S = 90° so Slope of SP = 1

P(10,2)

One solution.

Step-by-step explanation:

So we have:

2x + 3 = 4x + 2

Simplifying gives;

4x - 2x = 3 - 2

2x = 1

x = 1/2

There is only one solution here.

*Note: This questions are simple. You just have to do a little more practice on algebra if you are stuck.