Mathematics: Geometry! 6.) find the measure of a.

Geometry! 6.) find the measure of a.

Ответ:

lyn36

05.01.2022

Use the law of cosines.
a^2 = b^2 + c^2 - 2bc(cos(A))
a^2 = 11^2 + 8^2 - 2(11)(8)cos(32.2)
a^2 = 121 + 64 - 176cos(32.2)
a^2 = 185 - 176cos(32.2)
a^2 = 36.0700028
a = 6

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Ответ:

chanahvanya

18.07.2021

Mathematics

For this case what we are going to do is describe the work part by part:

1) Talib made the correct variable change in the first step.

2) Talib made a correct clearance in the second step by passing the number 4 subtracting.

3) Taliz made a correct clearance in the third step by passing the number -8 dividing.

4) Taliz made an incorrect variable change in the last step.

The correct variable change is:

$f(x)^{-1}=\frac{x-4}{-8}$

Error in the last step, the correct solution is:

$f(x)^{-1}=\frac{x-4}{-8}$

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Geometry!
6.) find the measure of a.

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