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Lena904
30.07.2019 •
Mathematics
Give the values a, b, and c needed to write the equations standard form. 2/3(x-4)(x+5)=1
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Ответ:
ax ^ 2 + bx + c
What we must do in this case is to rewrite the given equation.
We have then:
2/3 (x-4) (x + 5) = 1
(x-4) (x + 5) = 3/2
(x ^ 2 + 5x-4x-20) = 3/2
2x ^ 2 + 2x-40 = 3
2x ^ 2 + 2x-43 = 0
Thus, the values of a, b and c are:
a = 2
b = 2
c = -43
a = 2
b = 2
c = -43
Ответ:
-7,14,-28,56,-112
an = a1(r)^n-1
a4 = -7(-2)^4-1
a4 = -7(-2)³
a4 = -7(-8)
a4 = 56
an = a1(r)^n-1
a5 = -7(-2)^5-1
a5 = -7(-2)⁴
a5 = -7(16)
a5 = -112
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