Given a point on the terminal side of
functions of e.
trigonometry
(answer id # 0480248)
in standard position, find the exact value of the six trigonome
1. p(8, 2)
cot 8 =
sec @ =
sin
=
csc 8 =
cos 8 =
sec @ =
core -
sine =
sece -
2. p(-5, -1)
csc o =
cot @ =
csc b =
cose =
sine -
cos @ =
tan =
ane =
core
cos @ =
sine =
cose
sin e =
3. p(3,-8)
tan =
sece -
sec 0 =
esce
csc
=
sin 8 =
cot @ =
cos 6 =
4. p(9,-9)
cot 8 =
cos 8 =
tan 6 =
sin =
sec @ =
csc 8 =
p(-4,6)
tan 8 =
sece =
sec 8 =
sine -
sin 8
=
cote
cot 8 =
asce
csc
=
cose =
cos 6 =
6. p(-7, 7)
csc @ =
sin 0 =
tan 8 =
cot @ =
cos =
sec =
7. p(-1,-4)
tan 6 =
dan ?
see =
sec 2 =
cot 8 =
cote -
csc
see
=
sine =
sin 8 =
cose =
cos @ =
8. p(2,5)
tan 8 =
sec 8 =
csc 8 =
cot =
cos 8 =
sin 8 =
9. p(-6, 3)
cos 8 =
tan 8 =
csc @ =
cot 8 =
sec 0
=
sin @ =
10. p(3, 4)
cos 8 =
sec =
cot @ =
csc
=
tan 8 =
sin
=
4, 6, 8, 9

Median = 46.5

Minimum = 32

Maximum = 62

Lower quartile = 38

Upper quartile = 59

Step-by-step explanation:

Before we can proceed to solving any of these, it is best you arrange your data first from least to greatest

32  34  37  39  41  45  48  53  58  60  61  62

First we have the median. The Median is the middle value. In this case we an even number of data, which is 12 data points. The middle value of the data would be found in between the 6th and 7th data point:

45 and 48

To get the middle value, you need to solve for the value that is in the middle of 45 and 48 by getting the sum of both numbers and dividing it by two.

45 + 48 = 93

93 ÷ 2 = 46.5

The minimum and maximum value is merely the least and greatest number.

Here we have:

Minimum = 32

Maximum = 62

To get the lower and upper quartiles, just remember that quartiles divide the data into 4 equal parts. All you need to do is find the value that is in between each quarters of the data:

            Q1 (Lower)  Q2(Median) Q3(Upper)

32  34  37 |  39  41  45 | 48  53  58 | 60  61  62

Like the median, we will find the value that comes in between each quarter.

Q1

37 + 39 = 76

76 ÷ 2 = 38

Lower quartile = 38

Q3:

58 + 60 = 118

118 ÷ 2 = 59

Upper quartile = 59