Mathematics: Given area of a rectangle: 7x^2+57x+8 Find Perimeter:

Given area of a rectangle: 7x^2+57x+8 Find Perimeter:

zitterkoph

29.01.2022

Perimeter of the rectangle is 16x+18 units.

Step-by-step explanation:

The area of rectangle is

7x^2+57x+8

First we have to find the factor form of above expression.

Splitting the middle term, we get

7x^2+56x+x+8

7x(x+8)+1(x+8)

(x+8)(7x+1)

Area of a rectangle is the product of its dimensions. It means dimensions of the rectangle are (x+8) and (7x+1).

Perimeter of a rectangle is

Perimeter=2(l+b)

Perimeter=2[(x+8)+(7x+1)]

Perimeter=2[8x+9]

Perimeter=16x+18

Therefore, the perimeter of the rectangle is 16x+18 units.

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