Mathematics: Given ax^+bx+c=2(1.2x+0.3)(x-0.5)+(0.5x^+2.5x-1.3). what are the values of a,b, and c?

Given ax^+bx+c=2(1.2x+0.3)(x-0.5)+(0.5x^+2.5x-1.3). - id21203050525134910065, jeff7259

medinacamila1129

17.01.2022

For this case we must find the values a, b, c:

$2 (1.2x + 0.3) (x-0.5) + (0.5x ^ 2 + 2.5x-1.3) =\\(2.4x + 0.6) (x-0.5) + (0.5x ^ 2 + 2.5x-1.3) =$

We apply distributive property:

$(2.4x ^ 2-1.2x + 0.6x-0.3) + (0.5x ^ 2 + 2.5x-1.3) =\\(2.4x ^ 2-0.6x-0.3) + (0.5x ^ 2 + 2.5x-1.3) =$

We finish the term:

2.9x ^ 2 + 1.9x-1.6

$a = 2.9\\b = 1.9\\c = -1.6$

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ashiteru123

26.09.2022

So, the answer is B.The answer will be greater than $300 because 480 is greater than 100.

Step-by-step explanation:

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