Mathematics: Given cos theta = 4/5 and 0 theta 90; find sin 2 theta

Given cos theta = 4/5 and 0 theta 90; find sin - id450905447733, kaylinrebecca

Ответ:

2023apd

20.01.2022

Step-by-step explanation:

$cos \: \theta = \frac{4}{5} ..(given) \\ \\ \sin \: \theta = \sqrt{1 - {cos}^{2} \theta } \\ = \sqrt{1 - \bigg( \frac{4}{5} \bigg)^{2} } \\ = \sqrt{1 - \frac{16}{25} } \\ = \sqrt{ \frac{25 - 16}{25} } \\ = \sqrt{ \frac{9}{25} } \\ \therefore \sin \: \theta = \frac{3}{5} \\ \\ \sin \: 2\theta = 2\sin \: \theta \times \cos \: \theta \\ = 2 \times \frac{3}{5} \times \frac{4}{5} \\ \\ \huge \purple{ \boxed{ \therefore \sin \: 2\theta = \frac{24}{25} }}$

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Ответ:

sassy11111515

20.01.2022

Mathematics

24/25

Step-by-step explanation:

Cos(theta) = 4/5

5²-4² = 9

Sin(theta) = 3/5

Sin(2theta) = 2sin(theta)cos(theta)

= 2 × ⅘ × ⅗ = 24/25

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Ответ:

PineaPPle663

14.02.2020

Mathematics

10.5 Kb

Step-by-step explanation:

10.5 Kb total space cleared

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Given cos theta = 4/5 and 0 < theta < 90; find sin 2 theta

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