Mathematics: Given f(x) =1/(x^2+4) and g(x) = square root (x+1) Find g(f(x)).

Given f(x) =1/(x^2+4) and g(x) = square root (x+1)

kleathers97

21.08.2021

Step-by-step explanation:

all steps are in the picture above.

Note:if you have any question let me know about.thanks

0,0(0 оценок)

calistaallen1734

21.08.2021

9514 1404 393

g(f(x)) = √((x²+5)/(x²+4))

Step-by-step explanation:

$g(f(x))=g(\dfrac{1}{x^2+4})=\sqrt{\dfrac{1}{x^2+4}+1}=\sqrt{\dfrac{1+x^2+4}{x^2+4}}\\\\\boxed{g(f(x))=\sqrt{\dfrac{x^2+5}{x^2+4}}}$

I prefer this compact form, but some may want the denominator rationalized. This means the expression becomes ...

$g(f(x))=\sqrt{\dfrac{(x^2+5)(x^2+4)}{(x^2+4)^2}}\\\\\boxed{g(f(x))=\dfrac{\sqrt{x^4+9x^2+20}}{x^2+4}}$

0,0(0 оценок)

maya4790

29.07.2020

72 IS THE ANSWER

Step-by-step explanation:

BRAINLIEST PLEASE

0,0(0 оценок)