Given f(x)=x^2-4x+4 find the value(s) for x such that f(x)=25

To solve this, first factor f(x)

F(x) = (x-2)^2 = 25

Next, take the root of each side:

(x - 2) = +/- 5

So now we are left with two functions:

x - 2 = 5
x - 2 = -5

These yield the results
x = -3 & x = 7

So, for x = -3 & x= 7, f(x) will equal 25.

9)  2x - 9 < 7

Add 9 to both sides.

2x < 7 + 9

Simplify.

2x < 16

Divide both sides by 2.

x < 8

10)  Go through each answer choice & check.

a)  4n + 11 > -9

Subtract 11 from both sides.

4n > -9 - 11

Simplify.

4n > -20

Divide both sides by 4.

n > -5

(a) is incorrect.

b)  4n + 11 < -9

Subtract 11 from both sides.

4n < -9 - 11

Simplify.

4n < -20

Divide both sides by 4.

n < 5

(b) is incorrect

c)  -4n + 11 <-9

Subtract 11 from both sides.

-4n < -9 - 11

Simplify.

-4n < -20

Divide both sides by -4.

n > 5

(c) is incorrect

d)  -4n + 11 > -9

Subtract 11 from both sides.

-4n > -9 - 11

Simplify.

-4n > -20

Divide both sides by -4.

n < 5

(d) is correct

~Hope I helped!~