Mathematics: Given: in a right triangle, cot0 = 28/45 1. what is csc0 2. what is sec0

Given: in a right triangle, cot0 = 28/45 1. what - id02845110820320, caseyfriemoth1548

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18.03.2022

i) $cosec0 = \frac{hypotenuse}{opposite side} = \frac{53}{45}$

ii) $sec0 = \frac{hypotenuse}{adjacent side} = \frac{53}{28}$

Step-by-step explanation:

Step(i):-

Given that

$cot 0 = \frac{28}{45} = \frac{adjacentside}{opposite side}$

Hypotenuse AC² = AB²+BC²

⇒ AC² = 45²+28² = 2809

⇒ AC = √2809

⇒ AC = 53

Hypotenuse AC =53

Step(ii):-

i) $cosec0 = \frac{hypotenuse}{opposite side} = \frac{53}{45}$

ii) $sec0 = \frac{hypotenuse}{adjacent side} = \frac{53}{28}$

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