Mathematics: given: m∠aeb = 45° ∠aec is a right angle. prove: bisects ∠aec. proof: we are given that m∠aeb = 45° and ∠aec is a right angle. the measure of ∠aec is 90° by the definition of a right angle. applying the gives m∠aeb + m∠bec = m∠aec. applying the substitution property gives 45° + m∠bec = 90°. the subtraction property can be used to find m∠bec = 45°, so ∠bec ≅ ∠aeb because they have the same measure. since divides ∠aec into two congruent angles, it is the angle bisector.

Let s do this algebraically x + y = 17 (subtract)-(x - y = 29)x + y = 17-x + y = -292y = -12 divide both by 2y = -6 use this in an original equationx + y = 17x - 6 = 17 add 6 to both sidesx = 23our numbers are 23 and -6...

given: m∠aeb = 45° ∠aec is a right angle. prove:

Ответ:

jayjinks976

11.03.2022

Mathematics

Answer with explanation:

Given : $m\angle AEB=45^{\circ}$

$\angle AEC$ is a right angle.

$\angle AEC=90^{\circ}$

To prove that : Bisect $\angle AEC$ .

Proof: We are given that $m\angle AEB=45^{\circ}$

$\angle AEC=90^{\circ}$

By definition of a right angle.

$\angle AEB+\angle BEC=90^{\circ}$

45+ $\angle BEC=90$

By substitution property

$\angle BEC=90-45$

By subtraction property of equality

$\angle BEC=45^{\circ}$

So, $\angle BEC\cong \angle AEB$

Because they have the same measure.

Since BE divided the angle AEC into two congruent angles.Therefore, it is the angle bisector.

Hence proved.

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