Given m\parallel nm∥n, find the value of x. n m (8x+19)° 59°

Using the law of sines, SinA/a = SinB/b = SinC/c

guessing the triangle has a 90 degree angle J for the hyp. of 6 and another leg of 2, we set up the problem like this...

Sin90/6 = SinX/2   (multiply by 2)
2 [ Sin90/6 ] = Sinx
.333333333 = Sinx   (to change to degrees, use the Sin^-1 (.3333333333)
to get the approximate degrees of 19.47 degrees or 19.5 degrees.