Given p||q and r||s prove <4 is supplementary to <15

 x=6

Step-by-step explanation:

4(x+5)=9x+4x−34

Step 1: Simplify both sides of the equation.

4(x+5)=9x+4x−34

(4)(x)+(4)(5)=9x+4x+−34(Distribute)

4x+20=9x+4x+−34

4x+20=(9x+4x)+(−34)(Combine Like Terms)

4x+20=13x+−34

4x+20=13x−34

Step 2: Subtract 13x from both sides.

4x+20−13x=13x−34−13x

−9x+20=−34

Step 3: Subtract 20 from both sides.

−9x+20−20=−34−20

−9x=−54

Step 4: Divide both sides by -9.

−9x

−9

=

−54

−9