daquan20035
08.01.2021 •
Mathematics
Given \qquad m \angle QPS = 107^\circm∠QPS=107 ∘ m, angle, Q, P, S, equals, 107, degrees \qquad m \angle RPS = 4x + 27^\circm∠RPS=4x+27 ∘ m, angle, R, P, S, equals, 4, x, plus, 27, degrees \qquad m \angle QPR = 9x - 115^\circm∠QPR=9x−115 ∘ m, angle, Q, P, R, equals, 9, x, minus, 115, degrees Find m\angle QPRm∠QPRm, angle, Q, P, R:
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Ответ:
20°
Step-by-step explanation:
4x+27°+9x-115°=107°
4x+9x + 27°-115°=107°
13x-88°=107°
add 88 on both sides
13x=195°
divide 13 on both sides
x=15
9(15°)-115°
135°-115° = 20
The answer is 20
Ответ:
i feel you
Step-by-step explanation: