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kamiyaharris1
18.11.2020 •
Mathematics
Given that a bag of M & Ms has 21 brown candies, 15 orange candies, 10 yellow candies, 14 red candies, and 5 green candies, find the following probabilities. Enter all answers as reduced fraction. Do not use any spaces in your answers.
What is the probability of choosing a green M & M, eating it, and then choosing a brown M & M?
P( Answer
B | G
)= Answer
What is the probability of choosing a red M & M on the second try given that the first M & M was red and it was eaten?
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Ответ:
Step-by-step explanation:
These both are independent events. Neither is really a conditional probability. It's like asking "What the chances of getting a heads given that you got a tails in the previous through?" The answer is 1/2 if it is a fair coin.
So the total number of M and Ms is
21+ 15 + 10 + 14 + 5 = 65
5/65 * 14/64 = 0.0168 Be careful you you put that in your calculator.
Part B is a bit harder.
14/65 * 13/64 = 0.04375
Ответ:
True
Step-by-step explanation:
Example: 1.666666...
In that case, place the bar on top of the last 6