Given that f(x) = x^3, as x ---> -infinity, f(x) —> infinity.

true or false?

The standard form of the quadratic function is

y=ax∧2+bx+c

In order to determine the unknown parameters we will picked up three points from the given graph.

A(-1,-3) , B(0,-1) and C(1,5)

When we replace B coordinates in the quadratic function we get

-1= 0*a+0*b+c => c=-1   => y=ax∧2+bx-1

After that we will replace A and C coordinates in the quadratic equation and get

-3=a(-1)∧2+b(-1)-1 => -3=a-b-1 => a-b=-2

5=a*1∧2+b*1-1 => 5=a+b-1 => a+b=6

a-b=-2

a+b=6

When we add first equation to the second we get

2a=4 => a=2    When we replace a=2 in the first equation we get b=4

The quadratic function for the given graph is

y = 2x∧2+4x-1

Good luck!!!