Mathematics: Given the equation y=-2x^2+1. determine the direction of opening, coordinates of the vertex, maximum or minimum value and the axis of symmetry

Data:h (height) = 9 ftd (diameter) = 6 ftIf: d = 2*r → 6 = 2r → 2r = 6 → r = 6/2 → r = 3 ftFormula (cylinder)Solving:or Adopting: Solving:...

Given the equation y=-2x^2+1. determine the direction

Ответ:

badpotterchris

18.01.2022

Mathematics

The sign of the term in x^2 is negative so the graph will open downwards.
when x = 0 y = 1
The coordinates of the vertex are (0,1)
the maximum value of the function is 1
and the axis of symmetry ix x = 0 ( the y axis)

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Ответ:

Josephjenkins620

15.10.2022

Mathematics

Data:
h (height) = 9 ft
d (diameter) = 6 ft
If:
d = 2*r → 6 = 2r → 2r = 6 → r = 6/2 → r = 3 ft

Formula (cylinder)
$V = \pi *r^2*h$

Solving:
$V = \pi *r^2*h$
$V = \pi * 3^2 * 9$
$V = \pi *9*9$
$\boxed{V = 81 \pi\:ft^3}$

or

Adopting: $\pi \approx 3.14$
Solving:
$V = \pi *r^2*h$
V = 3.14 * 3^2 * 9

$\boxed{\boxed{V = 254.34\:ft^3}}\end{array}}\qquad\quad\checkmark$

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Given the equation y=-2x^2+1. determine the direction of opening, coordinates of the vertex, maximum or minimum value and the axis of symmetry

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