playboyG80
26.04.2021 •
Mathematics
Given the following point on the unit circle, find the angle, to the nearest tenth of a degree (if necessary), of the terminal side through that point, 0≤θ<360.
P=\left(\frac{\sqrt{2}}{2},-\frac{\sqrt{2}}{2}\right)
P=(
2
2
,−
2
2
ANSWER___
θ=360−45=315
-delta math
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Ответ:
y=(x+19)(x-9)
This is because 19*-9=-171 and 19-9=10.
Now to make x=0, you have to make the equation
x+19=0
and x-9=0
To solve, isolate x on both equations.
This makes x=-19 and x=9.