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joejoefofana
26.06.2019 •
Mathematics
Given the following sequence, find the 23rd term: 3, 5, 7, 9, 11, . . a. 50 b. 47 c. 25 d. 26
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Ответ:
B.47
Step-by-step explanation:
The formula for an arithmetic sequence is
an = a1+d(n-1)
a1 =3 (it is the first term)
We can find the common difference by taking the second term and subtracting the first term
5-3 =2
d=2
n = the term number we are looking for
an = 3 + 2(n-1)
We are looking for the 23rd term so n=23
a23 = 3 +2(23-1)
= 3 +2(22)
= 3+44
= 47
Ответ:
B. 47
Step-by-step explanation:
The sequence goes up by 2 each time, so to find the nth term, start with 2n.
For n = 1, 2n = 2(1) = 2, but we need 3, so modify to 2n + 1.
For n = 1, 2n + 1 = 2(1) + 1 = 2 + 1 = 3
For n = 2, 2n + 1 = 2(2) + 1 = 4 + 1 = 5
For n = 3, 2n + 1 = 2(3) + 1 = 6 + 1 = 7
Try n = 4 and 5, and you will get 9 and 11, respectively.
2n + 1 works for any term n, where n is natural number.
For the 23rd term, n = 23.
2n + 1 = 2(23) + 1 = 46 + 1 = 47
B. 47
Ответ: