Given the function f(x) = 0.5 |x– 4| – 3, for what values of x is f(x) =7 O x = -24, x = 16

O x= -16, x = 24

O x= -1, x = 9

O x= 1, x= -9

-16,24  B

Step-by-step explanation:

To solve this simplify the equation until it's just the absolute value brackets

7=.5 |x-4|-3

Add 3 to both sides and divide by .5 to get

20=|x-4|

Then solve this equation where the leftmost side is a positive and then a negative

So 20=x-4  

x=24

24 is one of our answers

Then solve it when the left side is a negative

-20=x-4

x=-16 which is the other answer

Answer:   i) both minima have the same x-value: 4ii) the minimum of the graph is greater thant the minumum of the function x² - 8x + 7.explanation: the second function is missing. i found it. it is given by a graph and i attache it.1) the two functions whose minima need to be compared are: a) f(x) = x² - 8x + 7, andb) the graph attached.2) the minimum of f(x) = x² - 8x + 7, may be found if you complete squares. and the minimum of the other function is read directly in the graph.3) complete squares for x² - 8x + 7.i) (x² - 8x + 16) - 16 + 7ii) (x - 4)² - 94) compare with the vertex form equation of the parabola: a(x - h)² + k, where the vertex is (h, k).∴ vertex = minimum = (4, -9)5) in the graph it is shown the vertex as (4, - 4).6) now you can answer: i) both minima have the same x-value: 4ii) the function x² - 8x + 7 has minimum equal to - 9, and the graph has minimum equal to - 4, so the minimum of the graph is greater.