Mathematics: Grade improvement and study motivation

Grade improvement and study motivation - id13923340, dgonzale1857

ryleeyeagley03

02.02.2021

x = 6.99in

Step-by-step explanation:

Given

l =2in

Volume = 72.66in^3

See attachment for prism

Required

Find x

The prism has a regular hexagon base

The base area is calculated as:

$Base\ Area= \frac{3\sqrt 3}{2}l^2$

This gives:

$Base\ Area= \frac{3\sqrt 3}{2} * 2^2$

$Base\ Area= \frac{3\sqrt 3}{2} * 4$

$Base\ Area= 3\sqrt 3 * 2$

$Base\ Area= 6\sqrt 3$

Side x represents the height.

So, we have:

$Volume = Base\ Area*x$

Make x the subject

$x = \frac{Volume }{ Base\ Area}$

$x = \frac{72.66in^3}{6\sqrt 3 in^2}$

$x = \frac{72.66}{6\sqrt 3}in$

$x = \frac{12.11}{\sqrt 3}in$

x = 6.99in --- approximated

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