Graph a line that contains the point (-5,-6) and has a slope of 2/3

We can start by using the formula y = mx + b

m = slope

b = y-intercept

we are already given our slope, so we can plug that in: y = 2/3 x + b

To find b, we can plug in (-5,-6) for x and y

-6 = 2/3 (-5) + b

multiply everything by 3 to get rid of the denominator

-18 = -10 + 3b

add 10 to both sides

-8 = 3b

divide

-8/3 = b

now that we have b, we now know the entire formula:

y = 2/3 x - 8/3 is a line that contains the point (-5,-6) and has a slope of 2/3

Use the formula (base1+base2)/2 multiplied by height(3 in)

Step-by-step explanation: I can't see what the bottom base is, but lets say it is 12. 5+12=17, and 17/2=8.5. 8.5*3=25.5

25.5