Gunther invested $10,000 in two mutual funds. one of the fun rose 6% in one year, and the other rose 9% in one year. if gunther's investment rose a total of $684 in one year how much did he invest in each mutual fund.

The amount invested at 6% was $7,200 and the amount invested at 9% was $2,800

Step-by-step explanation:

Let

x ----> the amount invested at 6%

10,000-x -----> the amount invested at 9%

we know that

The interest earned in one year by the amount invested at 6% plus the interest earned by the amount invested at 9% must be equal to $684

Remember that

so  

The linear equation that represent this problem is

solve for x

therefore

The amount invested at 6% was $7,200 and the amount invested at 9% was $2,800

i thank it is

130

Step-by-step explanation:

hope this is right

if not so sorry