Haley measured the distances between her house and two of her friends’ houses. ellen’s house is 1.41 miles away from haley’s, and dirk’s house is 6,547 feet away from haley’s. whose house is farther away from haley’s, and how many feet farther away is it, to the nearest whole foot?

Ellen's house is further away from Haley's
difference is approximately 898 ft (to the nearest foot)

Explanation:
To compare distances, we first need to unify the units.
So we will simply convert the miles into ft as follows:
we know that one mile is equivalent to 5280 ft.
To know the equivalence of 1.41 miles in ft, we will simply use cross multiplication as follows:
1 mile > 5280 ft
1.41 miles > ?? ft
1.41 miles = (1.41 * 5280) / 1 = 7444.8 ft

Now, let's compare distances:
We know that:
Ellen's house is 7444.8 ft away
Dirk's house is 6547 ft away
We can simply note that Ellen's house is further away from Haley's.

Finally, we will get the difference between the two as follows:
difference = 7444.8 - 6547 = 897.8 ft which is approximately 898 ft (to the nearest foot)

Hope this helps :)

Ellen's house is farther from Haley's because 1.41 miles = 7444.8 feet. It is also 898 feet farther away because 7444.8-6547 = 897.8, then you round to the nearest foot, giving you 898 feet.

The answer is x=3.6 . First, you'd cross multiply 6 by 9, and then divide it by 15.