Mathematics: Half of the product of two consecutive numbers is 105. which equation can be used to solve for n, the smaller of the two numbers? n2 + n – 210 = 0 n2 + n – 105 = 0 2n2 + 2n + 210 = 0 2n2 + 2n + 105 = 0

It equals 106293.086667 or simplified 106293 as a whole number....

Half of the product of two consecutive numbers

ramzieboy13

30.05.2020

Option A - n^2+n-210=0

Step-by-step explanation:

Given : Half of the product of two consecutive numbers is 105.

To find : Which equation can be used to solve for n, the smaller of the two numbers?

Solution :

Let,

Smaller of the two integers = n

Larger of the two integers = n + 1

Then, according to question

$\frac{1}{2}[n \times (n+1)]=105$

$[n^2+n]=105\times 2$

[n^2+n]=210

n^2+n-210=0

Therefore, Option A is correct.

The equation can be used to solve for n, n^2+n-210=0

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