Heating and cooling bills will be about % less than in a similar wood-framed building in upstate New York. An ICF home will be approximately % more expensive to construct than a wood-framed home. For a typical ft home costing $ ft to construct in upstate New York and costing $ per month to heat and cool, how many months does it take for a ft ICF home to pay back its extra construction cost?

Complete question :

Insulated concrete forms (ICF) can be used as a substitute for conventional wood framing in building construction. Heating and cooling bills will be about 60% less than in a similar wood-framed building in upstate New York. An ICF home will be approximately 10% more expensive to construct than a wood-framed home. For a typical 1,800 ftsquared2 home costing $130 ftsquared2 to construct in upstate New York and costing $260 per month to heat and cool, how many months does it take for a 1,800 ftsquared2 ICF home to pay back its extra construction cost?

150 months

Step-by-step explanation:

Wood framing Construction cost :

Cost per ft² = $130

Total cost for 1800 ft² :

1800 * $130 = $234,000

Heating and cooling cost = $260

An ICF home:

Construction cost will be approximately 10% more expensive :

Hence, total cost of ICF = (1.1) * 234000 = $257,400

Extra cost on construction :

$257,400 - $234000 = $23,400

Heating and cooling cost ; 60% less expensive = (1 - 0.6) * $260 = $104

Saving in heating and cooling = $260 - $104 = $156 monthly

Number of months it takes to pay extra cost on construction :

Extra cost on construction / saving in heating & cooling

= $23,400 / $156

= 150 months

Hello! In one mile, the wheel of the scooter will rotate exactly 754.2857 times. Don't forget to round that decimal to however many points your teacher has requested (for example: if they want your final answer to have to the nearest tenth you would round it to 754.28) To get the second blank, simply multiply your rounded decimal by 10,000.

When the wheel rotates once, it travels a distance of seven feet. In all, as you can see by the information provided on the graph, there are about 5,280 feet in a mile. All you need to do to solve the initial problem is divide the number of feet in a mile by the number of feet traveled in one rotation.

I hope this was helpful. Have a wonderful day!