Mathematics: Helll plleeaassee (part 2) 3. consider the quadratic equation x^2 – 6x = –1. a. what is the value of the discriminant? explain. b. how many solutions does the quadratic equation have and are those solutions rational, irrational, or nonreal? explain. c. if the quadratic equation has real solutions, what are the solutions? explain. estimate irrational solutions to the nearest tenth.

Helll plleeaassee (part 2) 3. consider the quadratic

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sistersquad

14.03.2022

Mathematics

x=3+ √10

(x−3)^2 =10

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Helll plleeaassee (part 2) 3. consider the quadratic equation x^2 – 6x = –1. a. what is the value of

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Rententen3845

14.03.2022

Mathematics

x²– 6x = –1
x²-6x+1=0, a=1, b=-6, c=1
A. Discriminant
D=b² - 4ac= 36-4*1*1=32, D>0, so this equation has 2 real solutions
to find the x we need to use formula
B.
$x= \frac{-b+/- \sqrt{D} }{2a} 

 \sqrt{D} = \sqrt{32} = \sqrt{(16*2)} =4 \sqrt{2} ,

 \sqrt{D} =4 \sqrt{2} , irrational, 

so roots of the equation are going to be real irrational.

$

C.x=(-b+/-√D)/2a, x1=(6+4√2)/2 = 3+2√2=5.8 , x2=(6-4√2)/2=3-2√2=0.2

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jake56555

30.05.2023

Mathematics

140%

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