Helll Write the equation of the line passing through (2,3) and perpendicular to y = 2/3 x + 7.

A perpendicular line will, by definition, have the negative reciprocal of the slope of the original line, so we already know the slope of the new line is -1/4. Therefore, the second line has an equation of y = -1/4x + b, where b is the intercept. Since we have a point on this second line, we can solve for b (the intercept) by plugging in the x and y values of that point. Thus, 2 = -1/4(-12) + b. Simplifying, 2 = 3 + b, so b = -1. The equation of the second line is y = -1/4x - 1!

Step-by-step explanation:

Step-by-step explanation:

It is given that  two trapezoids that are KRBQ and PNCV are similar to each other that is trapezoid KRBQ∼trapezoid PNCV.

Following are the matched corresponding parts of the trapezoid KRBQ similar to the trapezoid PNCV:

1. BQ is similar to CV

2. ∠R is similar to ∠N

3. KR  is similar to PN

4. ∠Q is similar to ∠V