Mathematics: HELLLPPP PLSSSSS(don’t answer if you aren’t serious this is important)

HELLLPPP PLSSSSS(don’t answer if you aren’t serious

Ответ:

steven123pink

17.03.2022

Mathematics

9514 1404 393

∠Q ≅ ∠U∠Q ≅ ∠U'∠S ≅ ∠V

Step-by-step explanation:

The following angles are equivalent:

Q = U = 45°

R = T = W = 225°

S = V = 90°

X = 135°

Reflection, any rigid transformation, or any uniform dilation will not change the measures of the angles. That is, U = U', for example.

So, the true angle statements are ...

∠Q ≅ ∠U∠Q ≅ ∠U'∠S ≅ ∠V

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Ответ:

meganpaughstu

13.09.2022

Mathematics

$\dfrac{7}{6}$

Step-by-step explanation:

Let $\dfrac{a}{b}$ be the original fraction.

If the numerator of a fraction is increased by six, the value of the fraction will increase by one. Hence,

$\dfrac{a+6}{b}=\dfrac{a}{b}+1$

If the denominator of the original fraction is increased by 36, the value of the original fraction will decrease by one. Hence,

$\dfrac{a}{b+36}=\dfrac{a}{b}-1$

Add these two equalities:

$\dfrac{a+6}{b}+\dfrac{a}{b+36}=\dfrac{a}{b}+1+\dfrac{a}{b}-1\\ \\\dfrac{a+6}{b}+\dfrac{a}{b+36}=2\dfrac{a}{b}\\ \\\dfrac{a}{b+36}=\dfrac{2a-(a+6)}{b}\\ \\\dfrac{a}{b+36}=\dfrac{a-6}{b}\\ \\ab=(a-6)(b+36)\\ \\ab=ab+36a-6b-216\\ \\36a-6b-216=0\\ \\6a-b-36=0\\ \\b=6a-36$

Substitute it into the first equation:

$\dfrac{a+6}{6a-36}=\dfrac{a}{6a-36}+1\\ \\\dfrac{a+6}{6(a-6)}=\dfrac{a}{6(a-6)}+1\\ \\a+6=a+6(a-6)\\ \\a+6=a+6a-36\\ \\6a=6+36\\ \\6a=42\\ \\a=7\\ \\b=6\cdot 7-36=42-36=6$

Thus, the initial fraction was

$\dfrac{7}{6}$

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HELLLPPP PLSSSSS(don’t answer if you aren’t serious this is important)

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