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sabrinakholikov
31.10.2020 •
Mathematics
HELP ME ASAP!! Consider the graph of the system of equations. Part A: What is the system of equations that is represented by the graph shown? Part B: What is the solution to the system of equations written in Part A? Show your work.
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Ответ:
Step-by-step explanation:
Part (A)
From the picture attached,
Line 1 passes through two points (-2, 0) and (-1, 3).
Let the equation of the line is,
y = mx + b
where m = slope of the line
b = y-intercept
Slope of a line passing through
and
is given by,
m =![\frac{y_2-y_1}{x_2-x_1}](/tpl/images/0857/7266/f6758.png)
Therefore, slope of line 1,
m =![\frac{3-0}{-1+2}](/tpl/images/0857/7266/5dcd6.png)
m = 3
y-intercept 'b' = 6
Equation of line 1 will be,
y = 3x + 6 --------(1)
Let the equation of line 2 is,
y = m'x + b'
Since line 2 passes through two points (0, -1) and (1, 3)
Slope m' =![\frac{3+1}{1-0}](/tpl/images/0857/7266/c7256.png)
= 4
y-intercept b' = -1
Equation of line 2 is,
y = 4x - 1 --------(2)
Part (B)
By equating the values of y from both the equations,
3x + 6 = 4x - 1
4x - 3x = 6 + 1
x = 7
From equation (2),
y = 4(7) - 1
= 28 - 1
= 27
Ответ:
I'm sure the answer is A
Step-by-step explanation: There is none, I saw someone else answer this.