HELP PLEASE IT'S DUE

  t(d) = 0.01cos(5π(d-0.3)/3)

Step-by-step explanation:

Since we are given the location of a maximum, it is convenient to use a cosine function to model the torque. The horizontal offset of the function will be 0.3 m, and the horizontal scaling will be such that one period is 1.2 m. The amplitude is given as 0.01 Nm.

The general form is ...

  torque = amplitude × cos(2π(d -horizontal offset)/(horizontal scale factor))

We note that 2π/1.2 = 5π/3. Filling in the given values, we have ...

  t(d) = 0.01·cos(5(d -0.3)/3)