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deadlydazy13
15.07.2020 •
Mathematics
Help would be appreciated.
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Ответ:
Step-by-step explanation:
1). f(x) = x² - 9
g(x) = x - 3
h(x) = f(x) ÷ g(x)
=![\frac{x^2-9}{x-3}](/tpl/images/0706/8429/b46f8.png)
=![\frac{(x+3)(x-3)}{(x-3)}](/tpl/images/0706/8429/5d6b4.png)
= (x + 3)
2). f(x) = x² - 4x + 3
= x² - 3x - x + 3
= x(x - 3) - 1(x - 3)
= (x - 1)( x- 3)
g(x) = x - 3
h(x) = f(x) ÷ g(x)
=![\frac{(x-1)(x-3)}{(x-3)}](/tpl/images/0706/8429/1e01a.png)
= (x - 1)
3). f(x) = x² + 4x - 5
= x² + 5x - x - 5
= x(x + 5) - 1(x + 5)
= (x - 1)(x + 5)
g(x) = x - 1
h(x) = f(x) ÷ g(x)
=![\frac{(x-1)(x+5)}{(x-1)}](/tpl/images/0706/8429/e4184.png)
= (x + 5)
4). f(x) = x² - 16
= (x - 4)(x + 4) [Since a² - b² = (a - b)(a + b)]
g(x) = (x - 4)
h(x) = f(x) ÷ g(x)
=![\frac{(x-4)(x+4)}{(x-4)}](/tpl/images/0706/8429/dfc1d.png)
= (x + 4)
Ответ: