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jamarhroul
26.12.2020 •
Mathematics
Heyy could you help me out?
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Ответ:
The mid-point M is (2, 1). M lies in quadrant I, since the x-coordinate is positive and the y-coordinate is positive
Step-by-step explanation:
The coordinates of the midpoint (x, y) of the segment whose endpoints are (x1, y1) and (x2, y2) are x =
, y = ![\frac{y1+y2}{2}](/tpl/images/1007/9524/70f62.png)
∵ M is the midpoint of DE
∵ D = (-1, 4) and E = (5, -2)
∴ x1 = -1 and x2 = 5
∴ y1 = 4 and y2 = -2
→ Use the rule above to find x, y the coordinates of M
∵ x =
= ![\frac{4}{2}](/tpl/images/1007/9524/72c88.png)
∴ x = 2
∵ y =
= ![\frac{2}{2}](/tpl/images/1007/9524/b5497.png)
∴ y = 1
∴ The coordinates of the midpoint M are (2, 1)
∵ The x-coordinate is positive and the y-coordinate is positive
∴ M lies in the first quadrant (I)
The mid-point M is (2, 1). M lies in quadrant I, since the x-coordinate is positive and the y-coordinate is positive
Ответ: