Mathematics: Hope everyone can me i ll really need your

Hope everyone can me i ll really need your

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20lap01

10.03.2022

See below. The solutions are x=-1/3 and y=-4/3

Step-by-step explanation:

$\frac{1}{2}\log_2 y-\log_4 x = 1\\\frac{1}{2}\log_2 y = \log_4 x+1=\log_4x+\log_4 4=\log_4 4x\\\frac{1}{2}\log_2y = log_44x\\\frac{1}{2}\frac{\log_4y}{\log_4 2}=\log_4 4x\\\log_4y=\log_44x\\4^{\log_4y}=4^{\log_44x}\\y = 4x\\\\x-y = 1\\4x -y = 0\\\rightarrow\\3x=-1\implies x = -\frac{1}{3}, y=-\frac{4}{3}$

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laytonlutz

19.01.2021

Mathematics

Y=x^2 +6 . This would be graphed as a parabola. So it would curve down before changing direction and going back in the opposite direction. So it’s not linear function (a straight lined function)

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